tan半角公式的疑问1 tan(a/2)=sina/(1+cosa)2 tan(a/2)=[ sina/(1+cosa)] * [(1-cosa)/(1-cosa)]=(1-cosa)/sina第1个是恒等变形,没有改变a角的范围,两边且恒等;第2个是恒等变形吗?我觉得不是啊;显然是缩小了a角的
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![tan半角公式的疑问1 tan(a/2)=sina/(1+cosa)2 tan(a/2)=[ sina/(1+cosa)] * [(1-cosa)/(1-cosa)]=(1-cosa)/sina第1个是恒等变形,没有改变a角的范围,两边且恒等;第2个是恒等变形吗?我觉得不是啊;显然是缩小了a角的](/uploads/image/z/12515366-38-6.jpg?t=tan%E5%8D%8A%E8%A7%92%E5%85%AC%E5%BC%8F%E7%9A%84%E7%96%91%E9%97%AE1+tan%28a%2F2%29%3Dsina%2F%281%2Bcosa%292+tan%28a%2F2%29%3D%5B+sina%2F%281%2Bcosa%29%5D+%2A+%5B%281-cosa%29%2F%281-cosa%29%5D%3D%281-cosa%29%2Fsina%E7%AC%AC1%E4%B8%AA%E6%98%AF%E6%81%92%E7%AD%89%E5%8F%98%E5%BD%A2%2C%E6%B2%A1%E6%9C%89%E6%94%B9%E5%8F%98a%E8%A7%92%E7%9A%84%E8%8C%83%E5%9B%B4%2C%E4%B8%A4%E8%BE%B9%E4%B8%94%E6%81%92%E7%AD%89%EF%BC%9B%E7%AC%AC2%E4%B8%AA%E6%98%AF%E6%81%92%E7%AD%89%E5%8F%98%E5%BD%A2%E5%90%97%3F%E6%88%91%E8%A7%89%E5%BE%97%E4%B8%8D%E6%98%AF%E5%95%8A%EF%BC%9B%E6%98%BE%E7%84%B6%E6%98%AF%E7%BC%A9%E5%B0%8F%E4%BA%86a%E8%A7%92%E7%9A%84)
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