若a²+2a+b²-6b+10=0求a²-b²的值
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若a²+2a+b²-6b+10=0求a²-b²的值
若a²+2a+b²-6b+10=0求a²-b²的值
若a²+2a+b²-6b+10=0求a²-b²的值
a²+2a+b²-6b+10=0
——>(a+1)²+(b-3)²=0
解得a=-1 b=3
所以
a²-b²=-8