作业帮Problem1) Draw the Lewis structure and predict the geometries of the followingmolecules.(a) BeH2 (b) OF2 (c) PF3Problem2) Given(1) C(s) + O2(g) →CO2(g) ∆H = -393.5kJ(2) 2CO(g) + O2(g) →2CO2(g) ∆H = -566.0kJCalculate∆H for the re
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Problem1) Draw the Lewis structure and predict the geometries of the followingmolecules.(a) BeH2 (b) OF2 (c) PF3Problem2) Given(1) C(s) + O2(g) →CO2(g) ∆H = -393.5kJ(2) 2CO(g) + O2(g) →2CO2(g) ∆H = -566.0kJCalculate∆H for the re
Problem1) Draw the Lewis structure and predict the geometries of the followingmolecules.
(a) BeH2 (b) OF2 (c) PF3
Problem2) Given
(1) C(s) + O2(g) →CO2(g) ∆H = -393.5kJ
(2) 2CO(g) + O2(g) →2CO2(g) ∆H = -566.0kJ
Calculate∆H for the reaction C(s) + ½ O2(g) → CO2(g) ∆H =
Problem3) Explain,in terms of intermolecular forces,why
(1) Boiling point of O2 (-183oC)is higher than that of N2(-196oC).
(2) Boiling point of NO (-151oC)is higher than that of either O2 or N2.
Problem4) Graphene,a subject of Nobel prize in Physics in 2010,is separated fromgraphite,an ordinary carbon matter.Describe the characters of graphene andthe method to separate in terms of intermolecular forces.
Problem1) Draw the Lewis structure and predict the geometries of the followingmolecules.(a) BeH2 (b) OF2 (c) PF3Problem2) Given(1) C(s) + O2(g) →CO2(g) ∆H = -393.5kJ(2) 2CO(g) + O2(g) →2CO2(g) ∆H = -566.0kJCalculate∆H for the re
英语能力有限……只能给中文答案了
1.
BeH2：H-Be-H 直线型
OF2：F-O-F V型分子
PF3：F-P-F 三角形分子
|
F
2.ΔH=ΔH1-½ΔH2=-676.5KJ
3.
（1）熔沸点与分子的分子间力即范德华力有关 主要是看分子的相对分子量的大小 因为氧气的分子量16大于氮气的14 所以其沸点要高
（2）NO是极性分子,不对称
4.
石墨烯是分子构成 属于分子晶体 作用力肯定是范德华力了
石墨烯及其衍生物的有效分离方法都是基于离心分离的