2^n.sinπ/2^n (n趋近无穷),求极限,用两个重要极限公式求
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2^n.sinπ/2^n (n趋近无穷),求极限,用两个重要极限公式求
2^n.sinπ/2^n (n趋近无穷),求极限,用两个重要极限公式求
2^n.sinπ/2^n (n趋近无穷),求极限,用两个重要极限公式求
=lim[sin(π/2^n)/(π/2^n)]·n
=1·n
=n
2^n.sinπ/2^n (n趋近无穷),求极限,用两个重要极限公式求
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