梯形中位线的位置判定已知:在梯形ABCD中,点E·F分别为它两腰AD与BC上的中点 求证:EF//AB EF=1/2[AB+DC]希望大家能帮我解决
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![梯形中位线的位置判定已知:在梯形ABCD中,点E·F分别为它两腰AD与BC上的中点 求证:EF//AB EF=1/2[AB+DC]希望大家能帮我解决](/uploads/image/z/12568594-58-4.jpg?t=%E6%A2%AF%E5%BD%A2%E4%B8%AD%E4%BD%8D%E7%BA%BF%E7%9A%84%E4%BD%8D%E7%BD%AE%E5%88%A4%E5%AE%9A%E5%B7%B2%E7%9F%A5%EF%BC%9A%E5%9C%A8%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2C%E7%82%B9E%C2%B7F%E5%88%86%E5%88%AB%E4%B8%BA%E5%AE%83%E4%B8%A4%E8%85%B0AD%E4%B8%8EBC%E4%B8%8A%E7%9A%84%E4%B8%AD%E7%82%B9+%E6%B1%82%E8%AF%81%EF%BC%9AEF%2F%2FAB+EF%3D1%2F2%5BAB%2BDC%5D%E5%B8%8C%E6%9C%9B%E5%A4%A7%E5%AE%B6%E8%83%BD%E5%B8%AE%E6%88%91%E8%A7%A3%E5%86%B3)
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