求教一道高一数学题(解析几何)已知△ABC的顶点A(2,-4),两条内角平分线的方程分别是BE:x+y-2=0和CF:x-2y-6=0,求△ABC的三边所在的直线方程.这个题目的解法我明白的,就是想确认下
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![求教一道高一数学题(解析几何)已知△ABC的顶点A(2,-4),两条内角平分线的方程分别是BE:x+y-2=0和CF:x-2y-6=0,求△ABC的三边所在的直线方程.这个题目的解法我明白的,就是想确认下](/uploads/image/z/12586867-43-7.jpg?t=%E6%B1%82%E6%95%99%E4%B8%80%E9%81%93%E9%AB%98%E4%B8%80%E6%95%B0%E5%AD%A6%E9%A2%98%EF%BC%88%E8%A7%A3%E6%9E%90%E5%87%A0%E4%BD%95%EF%BC%89%E5%B7%B2%E7%9F%A5%E2%96%B3ABC%E7%9A%84%E9%A1%B6%E7%82%B9A%EF%BC%882%2C%EF%BC%8D4%EF%BC%89%2C%E4%B8%A4%E6%9D%A1%E5%86%85%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%E7%9A%84%E6%96%B9%E7%A8%8B%E5%88%86%E5%88%AB%E6%98%AFBE%EF%BC%9Ax%2By%EF%BC%8D2%3D0%E5%92%8CCF%EF%BC%9Ax%EF%BC%8D2y%EF%BC%8D6%3D0%2C%E6%B1%82%E2%96%B3ABC%E7%9A%84%E4%B8%89%E8%BE%B9%E6%89%80%E5%9C%A8%E7%9A%84%E7%9B%B4%E7%BA%BF%E6%96%B9%E7%A8%8B.%E8%BF%99%E4%B8%AA%E9%A2%98%E7%9B%AE%E7%9A%84%E8%A7%A3%E6%B3%95%E6%88%91%E6%98%8E%E7%99%BD%E7%9A%84%EF%BC%8C%E5%B0%B1%E6%98%AF%E6%83%B3%E7%A1%AE%E8%AE%A4%E4%B8%8B)
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