化简:(3-1)(3^35+3^49+3^48+.+3^2+3+1)(x-1)(x+1)=x^2-1 (x-1)(x^2+x+1)=x^3-1
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化简:(3-1)(3^35+3^49+3^48+.+3^2+3+1)(x-1)(x+1)=x^2-1 (x-1)(x^2+x+1)=x^3-1
化简:(3-1)(3^35+3^49+3^48+.+3^2+3+1)
(x-1)(x+1)=x^2-1 (x-1)(x^2+x+1)=x^3-1
化简:(3-1)(3^35+3^49+3^48+.+3^2+3+1)(x-1)(x+1)=x^2-1 (x-1)(x^2+x+1)=x^3-1
(x-1)(x+1)=x^2-1 (x-1)(x^2+x+1)=x^3-1
所以(x-1)[x^(n-1)+x^(n-2)+……+x+1]=x^n-1
所以原式=3^36-1
化简:(3-1)(3^35+3^49+3^48+.+3^2+3+1)(x-1)(x+1)=x^2-1 (x-1)(x^2+x+1)=x^3-1
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