一道高中数学题(容斥定理)n(A1∪A2∪...∪Am)=∑n(Ai)1≤i≤m-∑n(Ai∩Aj)1≤i≤j≤m+∑n(Ai∩Aj∩Ak)-…+(-1)m-1n(A1∩A2…∩Am)1≤I,j,k≤m注:m-1是-1的指数
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![一道高中数学题(容斥定理)n(A1∪A2∪...∪Am)=∑n(Ai)1≤i≤m-∑n(Ai∩Aj)1≤i≤j≤m+∑n(Ai∩Aj∩Ak)-…+(-1)m-1n(A1∩A2…∩Am)1≤I,j,k≤m注:m-1是-1的指数](/uploads/image/z/12600317-29-7.jpg?t=%E4%B8%80%E9%81%93%E9%AB%98%E4%B8%AD%E6%95%B0%E5%AD%A6%E9%A2%98%EF%BC%88%E5%AE%B9%E6%96%A5%E5%AE%9A%E7%90%86%EF%BC%89n%28A1%E2%88%AAA2%E2%88%AA...%E2%88%AAAm%29%3D%E2%88%91n%28Ai%291%E2%89%A4i%E2%89%A4m%EF%BC%8D%E2%88%91n%28Ai%E2%88%A9Aj%291%E2%89%A4i%E2%89%A4j%E2%89%A4m%EF%BC%8B%E2%88%91n%28Ai%E2%88%A9Aj%E2%88%A9Ak%29%EF%BC%8D%E2%80%A6%EF%BC%8B%28-1%29m-1n%28A1%E2%88%A9A2%E2%80%A6%E2%88%A9Am%291%E2%89%A4I%2Cj%2Ck%E2%89%A4m%E6%B3%A8%EF%BC%9Am-1%E6%98%AF-1%E7%9A%84%E6%8C%87%E6%95%B0)
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