关于泛函分析(functional analysis)的一道证明题,in a finite dimensional normed vector space,every closed and bounded subset is compact.
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![关于泛函分析(functional analysis)的一道证明题,in a finite dimensional normed vector space,every closed and bounded subset is compact.](/uploads/image/z/12608093-29-3.jpg?t=%E5%85%B3%E4%BA%8E%E6%B3%9B%E5%87%BD%E5%88%86%E6%9E%90%EF%BC%88functional+analysis%EF%BC%89%E7%9A%84%E4%B8%80%E9%81%93%E8%AF%81%E6%98%8E%E9%A2%98%2Cin+a+finite+dimensional+normed+vector+space%2Cevery+closed+and+bounded+subset+is+compact.)
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