(求步骤)已知f(x)=根号3sinx+cosx,x∈[π/3,2π/3],则f(x)最大值为

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(求步骤)已知f(x)=根号3sinx+cosx,x∈[π/3,2π/3],则f(x)最大值为
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(求步骤)已知f(x)=根号3sinx+cosx,x∈[π/3,2π/3],则f(x)最大值为
(求步骤)已知f(x)=根号3sinx+cosx,x∈[π/3,2π/3],则f(x)最大值为

(求步骤)已知f(x)=根号3sinx+cosx,x∈[π/3,2π/3],则f(x)最大值为
f(x)=根号3sinx+cosx
=2[sinxcos(π/6)+cosxsin(π/6)]
=2sin(x+(π/6))
而x∈[π/3,2π/3],
所以:π/2

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