有点难的二次函数设p是实数,二次函数y=x^2-2px-p的图像与x轴有两个不同的交点A(m,o),B(n,0).(1)求证:2pm+n^2+3p大于0;(2)如果A,B两点之间的距离不超过(2p-3)的绝对值,求p的最大值
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![有点难的二次函数设p是实数,二次函数y=x^2-2px-p的图像与x轴有两个不同的交点A(m,o),B(n,0).(1)求证:2pm+n^2+3p大于0;(2)如果A,B两点之间的距离不超过(2p-3)的绝对值,求p的最大值](/uploads/image/z/12646186-34-6.jpg?t=%E6%9C%89%E7%82%B9%E9%9A%BE%E7%9A%84%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0%E8%AE%BEp%E6%98%AF%E5%AE%9E%E6%95%B0%2C%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0y%3Dx%5E2-2px-p%E7%9A%84%E5%9B%BE%E5%83%8F%E4%B8%8Ex%E8%BD%B4%E6%9C%89%E4%B8%A4%E4%B8%AA%E4%B8%8D%E5%90%8C%E7%9A%84%E4%BA%A4%E7%82%B9A%28m%2Co%29%2CB%28n%2C0%29.%281%29%E6%B1%82%E8%AF%81%EF%BC%9A2pm%2Bn%5E2%2B3p%E5%A4%A7%E4%BA%8E0%EF%BC%9B%282%29%E5%A6%82%E6%9E%9CA%2CB%E4%B8%A4%E7%82%B9%E4%B9%8B%E9%97%B4%E7%9A%84%E8%B7%9D%E7%A6%BB%E4%B8%8D%E8%B6%85%E8%BF%87%EF%BC%882p-3%29%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%2C%E6%B1%82p%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC)
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