若Inx-Iny=a,则In(x/2)立方根-In(y/2)立方根等于--------

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/11 18:43:26
若Inx-Iny=a,则In(x/2)立方根-In(y/2)立方根等于--------
x){ѽ3B36QiL< }#竻MlNF%OvBMR>fP%Uk@@TheR@a# ҘRPD}c<;l7TUH$ő 9 ѨjcBB `ȒP9`I$D'61! DM] ̂xXB%h

若Inx-Iny=a,则In(x/2)立方根-In(y/2)立方根等于--------
若Inx-Iny=a,则In(x/2)立方根-In(y/2)立方根等于--------

若Inx-Iny=a,则In(x/2)立方根-In(y/2)立方根等于--------
In(x/2)立方根-In(y/2)立方根
=1/3(ln(x/2)-ln(y/2))
=1/3*(lnx-ln2-lny+ln2)
=1/3*(lnx-lny)
=a/3

Inx-Iny=a,
In(x/y) = a
In(x/2)立方根-In(y/2)立方根
= lg { [(x/2)立方根] / [(y/2)立方根] }
= lg [(x/y)立方根]
= 1/3 lg(x/y)
= 1/3 a

In(x/2)立方根-In(y/2)立方根
=1/3[ln(x/2)-ln(y/2)]
=1/3[(lnx-ln2)-(lny-ln2)]
=(lnx-lny)/3
=a/3