x^2-7x-8=0
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x^2-7x-8=0
x^2-7x-8=0
x^2-7x-8=0
因式分解得(x-8)(x+1)=0
所以x=8或x=-1
已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值
如果1+x+x^2+x^3=0,求x+x^2+X^3+x^4+x^5+x^6+x^7+x^8的值,
x/x-2+x-9/x-7=x+1/x-1+x-8/x-6,
x/x-2+x-9/x-7=x+1/x-1+x-8/x-6,
x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少?
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
(x+12)(x-2)+(x+7)(x+8)-(x+5)(x-10),其中x=2
x^2-8[x]+7=0,求x的值[x]表示x取整
x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=?
填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x
(x+1)/(x+2)+(x+8)/(x+9)解答x+1/x+2+x+8/x+9=x+2/x+3+x+7/x+8
当x=-3,x=0,x=2,x=7,x=8时,不等式x-2
已知x^2+8x-6=0,求x(x+1)(x+7)(x+8)的值
x^2+7x+8=0
x^2-7x-8=0
X-5+8*X=7*X-2*X-1
x-8/x-4=2-x-5/x-7
解方程】(x+8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)(x+8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)