求34,35题,

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求34,35题,
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求34,35题,
求34,35题,
 

求34,35题,
34、分子=(1+7)+(2+6)+(3+5)+(4+4)+(5+3)+(6+2)+(7+1)+8
=8+8+8+8+8+8+8+8
=8×8
=64
因此,原式=8×8÷(888888×888888)
=111111×111111
=12345654321
35、原式=(1-1/2)+(1-1/6)+.+(1-1/9900)
=1+1+1+.+1 (99个1) -(1/2+1/6+.+1/9900)
=99-[1/(1×2)+1/(2×3)+.+1/(99×100)
=99-[(1-1/2)+(1/2-1/3)+.+(1/99-1/100)]
=99-(1-1/100)
=99-1+1/100
=98+0.01
=98.01