八下相似三角形的问题在等腰三角形ABC中,底边BC=a,角A等于36度,角ABC的平分线交AC于D,角BCD的平分线交BD于K.设K=(根号5-1)/2,则DE为多少?此题答案为:K^2*a,求思路与过程
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![八下相似三角形的问题在等腰三角形ABC中,底边BC=a,角A等于36度,角ABC的平分线交AC于D,角BCD的平分线交BD于K.设K=(根号5-1)/2,则DE为多少?此题答案为:K^2*a,求思路与过程](/uploads/image/z/12955100-68-0.jpg?t=%E5%85%AB%E4%B8%8B%E7%9B%B8%E4%BC%BC%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E9%97%AE%E9%A2%98%E5%9C%A8%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E5%BA%95%E8%BE%B9BC%3Da%2C%E8%A7%92A%E7%AD%89%E4%BA%8E36%E5%BA%A6%2C%E8%A7%92ABC%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%E4%BA%A4AC%E4%BA%8ED%2C%E8%A7%92BCD%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%E4%BA%A4BD%E4%BA%8EK.%E8%AE%BEK%3D%28%E6%A0%B9%E5%8F%B75-1%29%2F2%2C%E5%88%99DE%E4%B8%BA%E5%A4%9A%E5%B0%91%3F%E6%AD%A4%E9%A2%98%E7%AD%94%E6%A1%88%E4%B8%BA%3AK%5E2%2Aa%2C%E6%B1%82%E6%80%9D%E8%B7%AF%E4%B8%8E%E8%BF%87%E7%A8%8B)
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