已知任意三角型abc,过a点做垂线到bc命点e,过b点做垂线到ac命为f,过c点做垂线到ab命点d,连接de和fe,出现角1和角2,证明两角相等.bc线上中间两个,把图画出来就自然明白了,中心交点命为o,上面
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![已知任意三角型abc,过a点做垂线到bc命点e,过b点做垂线到ac命为f,过c点做垂线到ab命点d,连接de和fe,出现角1和角2,证明两角相等.bc线上中间两个,把图画出来就自然明白了,中心交点命为o,上面](/uploads/image/z/12971058-42-8.jpg?t=%E5%B7%B2%E7%9F%A5%E4%BB%BB%E6%84%8F%E4%B8%89%E8%A7%92%E5%9E%8Babc%2C%E8%BF%87a%E7%82%B9%E5%81%9A%E5%9E%82%E7%BA%BF%E5%88%B0bc%E5%91%BD%E7%82%B9e%2C%E8%BF%87b%E7%82%B9%E5%81%9A%E5%9E%82%E7%BA%BF%E5%88%B0ac%E5%91%BD%E4%B8%BAf%2C%E8%BF%87c%E7%82%B9%E5%81%9A%E5%9E%82%E7%BA%BF%E5%88%B0ab%E5%91%BD%E7%82%B9d%2C%E8%BF%9E%E6%8E%A5de%E5%92%8Cfe%2C%E5%87%BA%E7%8E%B0%E8%A7%921%E5%92%8C%E8%A7%922%2C%E8%AF%81%E6%98%8E%E4%B8%A4%E8%A7%92%E7%9B%B8%E7%AD%89%EF%BC%8Ebc%E7%BA%BF%E4%B8%8A%E4%B8%AD%E9%97%B4%E4%B8%A4%E4%B8%AA%EF%BC%8C%E6%8A%8A%E5%9B%BE%E7%94%BB%E5%87%BA%E6%9D%A5%E5%B0%B1%E8%87%AA%E7%84%B6%E6%98%8E%E7%99%BD%E4%BA%86%2C%E4%B8%AD%E5%BF%83%E4%BA%A4%E7%82%B9%E5%91%BD%E4%B8%BAo%EF%BC%8C%E4%B8%8A%E9%9D%A2)
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