级数cos(π/3)+cos(π/9)+cos(π/27)+.判断收敛性过程尽量完整.
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级数cos(π/3)+cos(π/9)+cos(π/27)+.判断收敛性过程尽量完整.
级数cos(π/3)+cos(π/9)+cos(π/27)+.判断收敛性
过程尽量完整.
级数cos(π/3)+cos(π/9)+cos(π/27)+.判断收敛性过程尽量完整.
发散,an的极限是1
级数cos(π/3)+cos(π/9)+cos(π/27)+.判断收敛性过程尽量完整.
级数(1-cosπ/n)敛散性
cos^3(-π-α)
计算:cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)
cos^2α+cos^2(α+π/3)-cosαcos(α+π/3)化简
求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
求值:cos(π/11)-cos(2π/11)+cos(3π/11)-cos(4π/11)+cos(5π/11)
cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
高数中的无穷级数请问u=cos(nπ) 是发散还是收敛
级数n^2(1-cosπ/n)是收敛谢谢了啊
级数∑n^2/[cos(nπ+a)}^2的敛散性,
化简cos(π/9)cos(2π/9)cos(3π/9)cos(4π/9)=( ).请说明理由哦、
cos(π/3+x)+cos(π/3-x)
化简cos(1-π)+cos(3π+1)=
COS多少等于π/3?
化简 cos(a-π/3)
化简cos(3π+a)
cos(-2/3)π=?