x-y=3 x^2-y^2=6 x+y=?

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x-y=3 x^2-y^2=6 x+y=?
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x-y=3 x^2-y^2=6 x+y=?
x-y=3 x^2-y^2=6 x+y=?

x-y=3 x^2-y^2=6 x+y=?
答案是:2
因为
x-y=3
x^2-y^2=(x+y)×(x-y)=6
x+y=2

y)^2
=x^2 2xy y^2
=x^2 xy y^2 xy
=6 10
=16
x^2-y^2
=x^2 xy-(y^2 xy)
=6-10
=-4
(x-y)^2
=((x^2-y^2)/(x y))^2
=(x^2-y^2)^2/(x y)^2
=(-4)^2/16
=1
看完了采纳哦~~

x-y=3
x²-y²=(x+y)(x-y)=6
x+y=2