已知三角形ABC,以BC为直径,O为圆心的半圆叫AC于F,点E为弧CF的中点,连接BE交AC于M,AD为△ABC的角平分线.且AD⊥BE,垂足为点H (1)求证:AB是半圆O的切线 (2)若AB=3,BC=4,求BE的长2、解∵AB⊥BC,AB=3,BC=
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![已知三角形ABC,以BC为直径,O为圆心的半圆叫AC于F,点E为弧CF的中点,连接BE交AC于M,AD为△ABC的角平分线.且AD⊥BE,垂足为点H (1)求证:AB是半圆O的切线 (2)若AB=3,BC=4,求BE的长2、解∵AB⊥BC,AB=3,BC=](/uploads/image/z/13232218-58-8.jpg?t=%E5%B7%B2%E7%9F%A5%E4%B8%89%E8%A7%92%E5%BD%A2ABC%2C%E4%BB%A5BC%E4%B8%BA%E7%9B%B4%E5%BE%84%2CO%E4%B8%BA%E5%9C%86%E5%BF%83%E7%9A%84%E5%8D%8A%E5%9C%86%E5%8F%ABAC%E4%BA%8EF%2C%E7%82%B9E%E4%B8%BA%E5%BC%A7CF%E7%9A%84%E4%B8%AD%E7%82%B9%2C%E8%BF%9E%E6%8E%A5BE%E4%BA%A4AC%E4%BA%8EM%2CAD%E4%B8%BA%E2%96%B3ABC%E7%9A%84%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF.%E4%B8%94AD%E2%8A%A5BE%2C%E5%9E%82%E8%B6%B3%E4%B8%BA%E7%82%B9H+%281%29%E6%B1%82%E8%AF%81%EF%BC%9AAB%E6%98%AF%E5%8D%8A%E5%9C%86O%E7%9A%84%E5%88%87%E7%BA%BF+%EF%BC%882%EF%BC%89%E8%8B%A5AB%3D3%2CBC%3D4%2C%E6%B1%82BE%E7%9A%84%E9%95%BF2%E3%80%81%E8%A7%A3%E2%88%B5AB%E2%8A%A5BC%2CAB%EF%BC%9D3%2CBC%EF%BC%9D)
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