解三元一次方程组 x+2y=2 2y+3z=4 x+3z=6

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解三元一次方程组 x+2y=2 2y+3z=4 x+3z=6
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解三元一次方程组 x+2y=2 2y+3z=4 x+3z=6
解三元一次方程组 x+2y=2 2y+3z=4 x+3z=6

解三元一次方程组 x+2y=2 2y+3z=4 x+3z=6
x+2y=2 (1)
2y+3z=4 (2)
x+3z=6(3)
(1)+(2)+(3)
2x+4y+6z=12
x+2y+3z=6(4)
(4)-(1)
得3z=4
z=4/3
(4)-(2)
得x=2
(4)-(3)
得2y=0
y=0
所以{x=2{y=0 {z=4/3

x+2y+z=4 (1) 4x-3z=1 (2) 2x+3y+4z=9 (3) (3)*2-(1)*3 3x+5z=6 (4) (2)*5+(4)*3 29x=23 x=23/29 z=21/29 y=36/29

X +2y=2
2y+3z=4
x+3z=6
合并1和2得:2-x+3z=4 =>
3z-x=2
x+3z=6 =>2+2x=6 => x=2
y=0 z=4/3

X +2y=2
2y+3z=4
x+3z=6
合并1和2得:2-x+3z=4 =>
3z-x=2
x+3z=6 =>2+2x=6 => x=2
y=0 z=4/3

x+2y=2
2y+3z=4
x+3z=6
x-3z= -2
x+3z=6
x=2
y=0
z=4/3