求∫1/sin^2xcos^2x dx

求∫1/sin^2xcos^2x dx 求不定积分,∫sin^2xcos^2x dx 求不定积分(1/sin^2xcos^2x)dx 求定积分∫(1/sin^2xcos^2x)dx上标派/3下标派/4 ∫(1/sin²xcos²x)dx怎么求, 求不定积分∫xcos(x^2)dx 求∫xcos^2(x)dx= ∫xcos(2x^2 -1)dx ∫xcos(1+x^2)dx= ∫1/(sin^2xcos^2x) 求不定积分：∫xcos(4x^2 +5)dx ∫xcos(2x)dx=?求过程qwq ∫(1/sin³xcos³x)dx 怎么解 ∫sin²xcos³x dx ∫xcos（x/2）dx 求下列不定积分.求详解（1）∫[(cos 2x)／(cos x﹢sin x)]dx; (2) ∫cot²xdx; (3) ∫{(1+2x²)／[x²(1+x²)]}dx; (4) ∫sin²(x／2)dx; (5) ∫[(cos2x)／(sin²xcos²x)]dx; (6) ∫[e^(x-4)]dx;求解 计算 ∫（上π 下-π） [sin^(2) x - xcos^(2) x]dx 急求∫tan^(-1)(1/x)dx 及 ∫sin^6xcos^2xdx详细解答,且要用到分部积分法的~