y=x^2/√[(2x+1)/(x-1)]用对数法求导 答案是y=x^2*√[(2x+1)/(xy=x^2/√[(2x+1)/(x-1)]用对数法求导答案是y=x^2*√[(2x+1)/(x-1)]*[4/x+2/(2x+1)-1/(x-1)]我写的是lny=2lnx+1/2ln(2x+1)-ln(x-1),算粗来跟答案不一样T^T

y=2x+√(1-x) 若√x-1-√1-x=(x+y)²先化简再求值：（1/2x）-(1/x+y)[x²-y²+(x+y/2x] 先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y 函数,y=3x/(x^2+x+1) ,x 函数y=3x/(x^2+x+1) （x 函数y=2x/x²-x+1（x 已知x+y=a,2x-y=-2a,求[（x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值 xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 求导y=2x^3-3x+(√x)-1/x√x y=(2x)/x-1化简成用y表示x 化简 3x(x^2-x-1)-(x+1)(3x^-x) X^3(x-y)+x(y-x) x+y=1,xy=-1/2,求x(x+y)(x-y)-x(x+y)2 (x-y)(y-x)-[x的平方-2x(x+y)]其中x=2分之1,y=-2 (x-y)(y-x)-[x²-2x(x+y)],其中x=1/2,y=-2 2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2 （x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3. mathematica软件,已知y[x],Y=f1(x),X(x)=f2(x),如何plot Y[X]?y[x_] := x + 9.81/2*x*xk=1X[x] = x - k*y'[x]/(1 + (y'[x])^2)^0.5Y[x] = y[x] + k/(1 + (y'[x])^2)^0.5Plot[{y[x],Y[X],},{x,0,2}]