实数m≠n且m²sinθ -mcosθ +π/3=0 n²sinθ -ncosθ +π/3=0则连接(m,m²)(n,n²)两点的直线与圆心在原点上的单位圆的位置关系是
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 17:05:21
![实数m≠n且m²sinθ -mcosθ +π/3=0 n²sinθ -ncosθ +π/3=0则连接(m,m²)(n,n²)两点的直线与圆心在原点上的单位圆的位置关系是](/uploads/image/z/13304000-56-0.jpg?t=%E5%AE%9E%E6%95%B0m%E2%89%A0n%E4%B8%94m%26%23178%3Bsin%CE%B8+-mcos%CE%B8+%2B%CF%80%2F3%3D0+n%26%23178%3Bsin%CE%B8+-ncos%CE%B8+%2B%CF%80%2F3%3D0%E5%88%99%E8%BF%9E%E6%8E%A5%EF%BC%88m%2Cm%26%23178%3B%EF%BC%89%EF%BC%88n%2Cn%26%23178%3B%EF%BC%89%E4%B8%A4%E7%82%B9%E7%9A%84%E7%9B%B4%E7%BA%BF%E4%B8%8E%E5%9C%86%E5%BF%83%E5%9C%A8%E5%8E%9F%E7%82%B9%E4%B8%8A%E7%9A%84%E5%8D%95%E4%BD%8D%E5%9C%86%E7%9A%84%E4%BD%8D%E7%BD%AE%E5%85%B3%E7%B3%BB%E6%98%AF)
x){nru.{cJuqf
@Z|Bdӎ/{ַ\1ty:ypK7|>-w霶Yo>PɎ.ީOl uO[7?ٌ6IEr4,\fdذG[:qC#~XUխ n(CO;6 u>ݶ %vp%Ps0%f jճ/.H̳E Э
实数m≠n且m²sinθ -mcosθ +π/3=0 n²sinθ -ncosθ +π/3=0则连接(m,m²)(n,n²)两点的直线与圆心在原点上的单位圆的位置关系是
实数m≠n且m²sinθ -mcosθ +π/3=0 n²sinθ -ncosθ +π/3=0
则连接(m,m²)(n,n²)两点的直线与圆心在原点上的单位圆的位置关系是
实数m≠n且m²sinθ -mcosθ +π/3=0 n²sinθ -ncosθ +π/3=0则连接(m,m²)(n,n²)两点的直线与圆心在原点上的单位圆的位置关系是
实数m≠n且m²sinθ -mcosθ +π/3=0 n²sinθ -ncosθ +π/3=0,
∴连接(m,m²)、(n,n²)两点的直线l:ysinθ-xcosθ+π/3=0,
∴原点到l的距离=π/3>1,
∴直线l与圆心在原点的单位圆相离.