作业帮已知x=(16/3)^0,y=-3,求[(2x-y)(-y-2y)-3x^2y-(y^2-4x^2)]/2x的值
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已知x=(16/3)^0,y=-3,求[(2x-y)(-y-2y)-3x^2y-(y^2-4x^2)]/2x的值
已知x=(16/3)^0,y=-3,求[(2x-y)(-y-2y)-3x^2y-(y^2-4x^2)]/2x的值
已知x=(16/3)^0,y=-3,求[(2x-y)(-y-2y)-3x^2y-(y^2-4x^2)]/2x的值
首先你可以得到x=1,y=-3
[(2x-y)(-y-2y)-3x^2y-(y^2-4x^2)]=(2+3)(3+6)+3*3-(9-4)=45+9-5=49
所以[(2x-y)(-y-2y)-3x^2y-(y^2-4x^2)]/2x的值=49/2
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