MATLAB 中已知a1=1;a2=2;a3=3;a4=4 b1=4;b2=3;b3=2;b4=1;怎么求 s(i)=a(i)+b(i)(i=1:4) 如:s1=a1+b1用eval函数:m=1:4eval(['s' num2str(m)])=eval(['a' num2str(m)])+eval(['b' num2str(m)])就会出现Index exceeds matrix dimensions.要不就是 Co
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![MATLAB 中已知a1=1;a2=2;a3=3;a4=4 b1=4;b2=3;b3=2;b4=1;怎么求 s(i)=a(i)+b(i)(i=1:4) 如:s1=a1+b1用eval函数:m=1:4eval(['s' num2str(m)])=eval(['a' num2str(m)])+eval(['b' num2str(m)])就会出现Index exceeds matrix dimensions.要不就是 Co](/uploads/image/z/13313618-26-8.jpg?t=MATLAB+%E4%B8%AD%E5%B7%B2%E7%9F%A5a1%3D1%3Ba2%3D2%3Ba3%3D3%3Ba4%3D4+b1%3D4%3Bb2%3D3%3Bb3%3D2%3Bb4%3D1%3B%E6%80%8E%E4%B9%88%E6%B1%82+s%28i%29%3Da%28i%29%2Bb%28i%29%28i%3D1%3A4%29+%E5%A6%82%EF%BC%9As1%3Da1%2Bb1%E7%94%A8eval%E5%87%BD%E6%95%B0%EF%BC%9Am%3D1%3A4eval%28%5B%27s%27+num2str%28m%29%5D%29%3Deval%28%5B%27a%27+num2str%28m%29%5D%29%2Beval%28%5B%27b%27+num2str%28m%29%5D%29%E5%B0%B1%E4%BC%9A%E5%87%BA%E7%8E%B0Index+exceeds+matrix+dimensions.%E8%A6%81%E4%B8%8D%E5%B0%B1%E6%98%AF+Co)
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