f(x)=-4sin(2x+π/6)-1的单调区间是多少?
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f(x)=-4sin(2x+π/6)-1的单调区间是多少?
f(x)=-4sin(2x+π/6)-1的单调区间是多少?
f(x)=-4sin(2x+π/6)-1的单调区间是多少?
F'=-8cos(2x+π/6),
F'=0,X=-π/3,π/6
-7π/12〈X〈-π/3,F'大于0,增区间
-π/3≤x≤π/6,F'小于0,减区间
π/6〈x《5π/12,F'大于0,增区间
傅里叶级数作图f(x)=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si
f(x)=-4sin(2x+π/6)-1的单调区间是多少?
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