解不等式什么情况下用十字相乘2X²-7X≤X²+12X²-7x-12≤0(x-3)(x-4)≤03≤x≤4这里x≤4 不是≥
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![解不等式什么情况下用十字相乘2X²-7X≤X²+12X²-7x-12≤0(x-3)(x-4)≤03≤x≤4这里x≤4 不是≥](/uploads/image/z/1333940-68-0.jpg?t=%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8F%E4%BB%80%E4%B9%88%E6%83%85%E5%86%B5%E4%B8%8B%E7%94%A8%E5%8D%81%E5%AD%97%E7%9B%B8%E4%B9%982X%26%23178%3B-7X%E2%89%A4X%26%23178%3B%2B12X%26%23178%3B-7x-12%E2%89%A40%28x-3%29%28x-4%29%E2%89%A403%E2%89%A4x%E2%89%A44%E8%BF%99%E9%87%8Cx%E2%89%A44+%E4%B8%8D%E6%98%AF%E2%89%A5)
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