解100(1+x)+100(1+x)^2=250求 100(1+x)+100(1+x)^2=250 的值(^2为平方)再麻烦问一下(根号11-3/2)约等于百分之几?
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![解100(1+x)+100(1+x)^2=250求 100(1+x)+100(1+x)^2=250 的值(^2为平方)再麻烦问一下(根号11-3/2)约等于百分之几?](/uploads/image/z/1333959-15-9.jpg?t=%E8%A7%A3100%EF%BC%881%2Bx%29%2B100%281%2Bx%29%5E2%3D250%E6%B1%82+100%EF%BC%881%2Bx%29%2B100%281%2Bx%29%5E2%3D250+%E7%9A%84%E5%80%BC%EF%BC%88%5E2%E4%B8%BA%E5%B9%B3%E6%96%B9%EF%BC%89%E5%86%8D%E9%BA%BB%E7%83%A6%E9%97%AE%E4%B8%80%E4%B8%8B%EF%BC%88%E6%A0%B9%E5%8F%B711-3%2F2%29%E7%BA%A6%E7%AD%89%E4%BA%8E%E7%99%BE%E5%88%86%E4%B9%8B%E5%87%A0%EF%BC%9F)
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解100(1+x)+100(1+x)^2=250求 100(1+x)+100(1+x)^2=250 的值(^2为平方)再麻烦问一下(根号11-3/2)约等于百分之几?
解100(1+x)+100(1+x)^2=250
求 100(1+x)+100(1+x)^2=250 的值
(^2为平方)
再麻烦问一下(根号11-3/2)约等于百分之几?
解100(1+x)+100(1+x)^2=250求 100(1+x)+100(1+x)^2=250 的值(^2为平方)再麻烦问一下(根号11-3/2)约等于百分之几?
教你方法,把1+X设为a,式子就变成了100a+100a'2=250了,然后就可以计算出a 的值,a 等于1加X.可以求出x
令x+1=t,则原方程可化为100t^2+100t-250=0
解出t就可以求得x了
100(1+x)+100(1+x)^2=250
10(1+x)+10(1+x)^2=25
10+10x+10+20x+10x^2=25
10x^2+30x-5=0
x=(根号11-3)/2或X=-(根号11+3)/2
解方程:2x+4x+6x...+100x=1-(x+3x+5x+...+99x)
x(x-1)(x-2)...(x-99)(x-100)
解方程2X+0+X*X+1=100
1/X(X+1)+1/(X+1)(X+2)+1/(X+2)(X+3).+1/(X+99)(X+100)=
1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+...+1/(x+100)(x+101)
1X+2X+3X…+98X+99X+100X=50500X X等于多少?
1x+2x+3x+4x+5x+6x+7x…+99x=100
计算1/X(X+1)+1/(X+1)(X+2)+.+1/(X+99)(X+100)
设函数f(x)=(x-1)(x-2)...(x-100)(x>100),求F'(X)
f(x)=x(x-1)(x-2)…(x-99)(x-100),求f'(100)
计算1/x(x+2)+1/(x+2)(x+4)+…+1/(x+98)(x+100)
1/2x+1=1/2-1/3x x-2x+3x-4x+...+99x-100x=25解方程
小学六年级下册数学解方程.. 要详细的.. 还要过程 都写下来...2x+3x=60 3.6x-2.8x=12 100x-x=198 18x+2x+60 5x+6x=12.1 6.6x-5x=8 4x-x=24 1.5x-x=1 1.9x+0.4x=9.2
已知x^4+x^3+x^3+x^2+x^1+1=0,求x^100+x^99+x^98+x^97+x^96的值
一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
一道数学题:1/x-1+1/(x-1)(x-2)+1/(x-2)(x-3)+.+1/(x-99)(x-100)
分式:计算1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+...+1/(x-99)(x-100)
1/(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)……+1/(x+99)(x+100)