作业帮f(x)=x(x-1)(x-2)…(x-99)(x-100),求f'(100)
来源：学生作业帮助网 编辑：作业帮 时间：2024/10/01 05:01:15
x)KӨдШ5FiKK@SƦ4u
&H$v6ckڣ@]`-TPb\?XZ* & TV@EϦoyOv}ֽiZlaϳg u=zf͓]=/W
f(x)=x(x-1)(x-2)…(x-99)(x-100),求f'(100)
f(x)=x(x-1)(x-2)…(x-99)(x-100),求f'(100)
f(x)=x(x-1)(x-2)…(x-99)(x-100),求f'(100)
∵f’(x)
=(x-100)’x(x-1)…(x-99)
+(x-100)[x(x-1)…(x-99)]’
而当x=100时,不管中括号的导数的值怎样,上式的第二部分积为0
∴f’(100)=100×99×…×1
=100!
f（100）=100×99×98×97……×1×0
＝0
85447
f(x)=x(x-1)(x-2)…(x-99)(x-100),求f'(100)
f(x)=x^2+x (x
f(x)={2x+1,x
f(x)={1+x/2,x
f(x)=(x-1)/(x+2)
f(x)=x(x-1)(x+2)(x-3)(x+4)……(x+100),求f'(1)
f(x)+f((x-1)/x)=2x; x!=0,1; 求f(x)
f(x)+f[(x-1)/x]=2x x不等于0,1.求f(x).
max{f(x),g(x)}=1/2(f(x)+g(x)+|f(x)-g(x)|
设f(x)=x(x-1)(x-2)……(x-100)求,f'(1)
f(x)=x(x-1)(x-2)…(x-99),怎么求f'(0)=?
已知f(x)=(x-1)(x-2)(x-3)…(x-2008),求f’(1).
f(x)=x(x-1)(x-2)…(x-100),求f'(100).
f(X)=f(X+2)(x
函数F(x)=2x,x>=1,F(x)=x^2,x
f(x)=|x+2|+|x-2|值域 f(x)=|x-2|-|x+1|值域
已知f(x+1/x)=x^2+1/x^2+1/x则f(x)
设2f(x)+xf(1/x)=(x+2x)/(x+1),求f(x).