这几道不定积分怎么解.1、Z(dx)/1+cos2、Z f(x)dx = Z (x)+c,则Z e^-x * f(e^-x)dx =3、f(x)=e^-x,则Q {f'(lnx)]/xdx=4、Q f(x)dx=xe^(2x)+c,则f(x)=5、Q [2x^2/(1+x^2)]dx=6、Q [3+x^2+x^3(开平方)/x^(1/2)]dxQ是不定积分符号,顺便
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![这几道不定积分怎么解.1、Z(dx)/1+cos2、Z f(x)dx = Z (x)+c,则Z e^-x * f(e^-x)dx =3、f(x)=e^-x,则Q {f'(lnx)]/xdx=4、Q f(x)dx=xe^(2x)+c,则f(x)=5、Q [2x^2/(1+x^2)]dx=6、Q [3+x^2+x^3(开平方)/x^(1/2)]dxQ是不定积分符号,顺便](/uploads/image/z/13354538-50-8.jpg?t=%E8%BF%99%E5%87%A0%E9%81%93%E4%B8%8D%E5%AE%9A%E7%A7%AF%E5%88%86%E6%80%8E%E4%B9%88%E8%A7%A3.1%E3%80%81Z%EF%BC%88dx%29%2F1%2Bcos2%E3%80%81Z+f%28x%29dx+%3D+Z+%28x%29%2Bc%2C%E5%88%99Z+e%5E-x+%2A+f%28e%5E-x%29dx+%3D3%E3%80%81f%28x%29%3De%5E-x%2C%E5%88%99Q+%7Bf%27%28lnx%29%5D%2Fxdx%3D4%E3%80%81Q+f%28x%29dx%3Dxe%5E%282x%29%2Bc%2C%E5%88%99f%28x%29%3D5%E3%80%81Q+%5B2x%5E2%2F%281%2Bx%5E2%29%5Ddx%3D6%E3%80%81Q+%5B3%2Bx%5E2%2Bx%5E3%28%E5%BC%80%E5%B9%B3%E6%96%B9%EF%BC%89%2Fx%5E%281%2F2%29%5DdxQ%E6%98%AF%E4%B8%8D%E5%AE%9A%E7%A7%AF%E5%88%86%E7%AC%A6%E5%8F%B7%2C%E9%A1%BA%E4%BE%BF)
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