a1=1,S(n+1)=4an+2(n属于N*)bn=a(n+1)-2an,求bn的通项公式1)求bn的通项公式,2)设cn=an/2^n,求证an是等差数列,3)求an通项公式和Sn
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![a1=1,S(n+1)=4an+2(n属于N*)bn=a(n+1)-2an,求bn的通项公式1)求bn的通项公式,2)设cn=an/2^n,求证an是等差数列,3)求an通项公式和Sn](/uploads/image/z/13391765-53-5.jpg?t=a1%3D1%2CS%28n%2B1%EF%BC%89%3D4an%2B2%28n%E5%B1%9E%E4%BA%8EN%2A%EF%BC%89bn%3Da%EF%BC%88n%2B1%EF%BC%89-2an%2C%E6%B1%82bn%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F1%EF%BC%89%E6%B1%82bn%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%2C2%EF%BC%89%E8%AE%BEcn%3Dan%2F2%5En%2C%E6%B1%82%E8%AF%81an%E6%98%AF%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%2C3%EF%BC%89%E6%B1%82an%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%E5%92%8CSn)
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