计算1/(m∧2-m)+(m-1)/(2m∧2-2),并求当m=3是的值
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计算1/(m∧2-m)+(m-1)/(2m∧2-2),并求当m=3是的值
计算1/(m∧2-m)+(m-1)/(2m∧2-2),并求当m=3是的值
计算1/(m∧2-m)+(m-1)/(2m∧2-2),并求当m=3是的值
1/(m∧2-m)+(m-1)/(2m∧2-2)
=1/m(m-1)+1/2(m+1)
=1/3×2+1/2×4
=1/6+1/8
=4/24+3/24
=7/24
1/(m∧2-m)+(m-1)/(2m∧2-2),
=1/m(m-1)+(m-1)/2(m+1)(m-1)
=1/m(m-1)+1/2(m+1)
=[2(m+1)+m(m-1)]/2m(m+1)(m-1)
=(2m+2+m^2-m)/2m(m+1)(m-1)
=(m^2+m+2)/2m(m+1)(m-1)
=(3^2+3+2)/2*3(3+1)(3-1)
=14/48
=7/24
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