{x+y-2z=5,2x-y-z=4,3x+y-3z=10,解三元一次方程,过程清楚些,
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![{x+y-2z=5,2x-y-z=4,3x+y-3z=10,解三元一次方程,过程清楚些,](/uploads/image/z/13414967-71-7.jpg?t=%7Bx%2By-2z%3D5%2C2x-y-z%3D4%2C3x%2By-3z%3D10%2C%E8%A7%A3%E4%B8%89%E5%85%83%E4%B8%80%E6%AC%A1%E6%96%B9%E7%A8%8B%2C%E8%BF%87%E7%A8%8B%E6%B8%85%E6%A5%9A%E4%BA%9B%2C)
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{x+y-2z=5,2x-y-z=4,3x+y-3z=10,解三元一次方程,过程清楚些,
{x+y-2z=5,2x-y-z=4,3x+y-3z=10,解三元一次方程,过程清楚些,
{x+y-2z=5,2x-y-z=4,3x+y-3z=10,解三元一次方程,过程清楚些,
由x+y-2z=5得2x+2y-4z=10
2x+2y-4z=10与2x-y-z=4相减得y-z=2
由x+y-2z=5得3x+3y-6z=15
3x+3y-6z=15与3x+y-3z=10相减得
由2y-2z=4与2y-3z=5得y=1 z=-1
代入原方程组解得x=2
综上x=2 y=1 z=-1
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
x/2=y/3=z/5 x+3y-z/x-3y+z
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
x+y=5 2x+3y-z=9 x-y+z=4
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
已知:4x-5y+2z=0 x+4y-3z=0则:(x*x+y*y+z*z)/(x*y+y*z+z*x)=____.
2x+z=10 x+y-z=4 3x-y-z=0
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
{ 5x-3y+z=25x+2y-4z=3-5x+y-z=2
x:y:z=3:4:5 2x-3y+2z=8 x-y-2z=?
x+y+z=4 2x-y+z=3 3x-2y-3z=-5
3x-2y+z=4 x+y-z=5 4x-4y+3z=27
x-y+z=-1 5x+2y-z=6 4x-3y+2z=-5