[(m+2n)(m-2n)-(m-2n)∧2]÷(-3n)∧2
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[(m+2n)(m-2n)-(m-2n)∧2]÷(-3n)∧2
[(m+2n)(m-2n)-(m-2n)∧2]÷(-3n)∧2
[(m+2n)(m-2n)-(m-2n)∧2]÷(-3n)∧2
解[(m+2n)(m-2n)-(m-2n)∧2]÷(-3n)∧2
=[m^2-4n^2-(m^2-4mn+4n^2)]÷(-3n)∧2
=(4mn-8n^2)/9n^2
=(4m-8n)/9n
(1),(-m-n)(-m+n) (2),(-m+n)(m-n)
(m-2n)(-m-n)
m-n+2n^2/(m+n)
(m-2n/n-m)-(n/m-n)=
2(m-n)²-m(m-n)
(m-n)(m+n)+(m+n)²-2m²
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(n/m+n/2m^2)*4m/n^2
m/(m-n)^2-n/(n-m)^2
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