接下列一元二次方程:如:3x^2-10x+3=0x=-(-10)±√(-10)^2-4x3x3/2X3x=10±√100-36/6x=10±√64/6x=10±8/6x=18/6=3x=2/6=1/3x1=10+8/6=3x2=10-8/6=2/6=1/3 .x^2-3x+2=0,5x^2-x-6=0,4x^2-4x+1=0
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/03 18:30:41
![接下列一元二次方程:如:3x^2-10x+3=0x=-(-10)±√(-10)^2-4x3x3/2X3x=10±√100-36/6x=10±√64/6x=10±8/6x=18/6=3x=2/6=1/3x1=10+8/6=3x2=10-8/6=2/6=1/3 .x^2-3x+2=0,5x^2-x-6=0,4x^2-4x+1=0](/uploads/image/z/13567336-16-6.jpg?t=%E6%8E%A5%E4%B8%8B%E5%88%97%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8B%EF%BC%9A%E5%A6%82%EF%BC%9A3x%5E2-10x%2B3%3D0x%3D-%28-10%29%C2%B1%E2%88%9A%28-10%29%5E2-4x3x3%2F2X3x%3D10%C2%B1%E2%88%9A100-36%2F6x%3D10%C2%B1%E2%88%9A64%2F6x%3D10%C2%B18%2F6x%3D18%2F6%3D3x%3D2%2F6%3D1%2F3x1%3D10%2B8%2F6%3D3x2%3D10-8%2F6%3D2%2F6%3D1%2F3+.x%5E2-3x%2B2%3D0%2C5x%5E2-x-6%3D0%2C4x%5E2-4x%2B1%3D0)
接下列一元二次方程:如:3x^2-10x+3=0x=-(-10)±√(-10)^2-4x3x3/2X3x=10±√100-36/6x=10±√64/6x=10±8/6x=18/6=3x=2/6=1/3x1=10+8/6=3x2=10-8/6=2/6=1/3 .x^2-3x+2=0,5x^2-x-6=0,4x^2-4x+1=0
接下列一元二次方程:
如:3x^2-10x+3=0
x=-(-10)±√(-10)^2-4x3x3/2X3
x=10±√100-36/6
x=10±√64/6
x=10±8/6
x=18/6=3
x=2/6=1/3
x1=10+8/6=3
x2=10-8/6=2/6=1/3 .
x^2-3x+2=0,
5x^2-x-6=0,
4x^2-4x+1=0
接下列一元二次方程:如:3x^2-10x+3=0x=-(-10)±√(-10)^2-4x3x3/2X3x=10±√100-36/6x=10±√64/6x=10±8/6x=18/6=3x=2/6=1/3x1=10+8/6=3x2=10-8/6=2/6=1/3 .x^2-3x+2=0,5x^2-x-6=0,4x^2-4x+1=0
x^2-3x+2=0,
x=-(-3)±√(-3)^2-4x2x1/2X1
x=3±√1/2
x=3±1/2
x1=3+1/2=2
x2=3-1/2=1
5x^2-x-6=0,
x=-(-1)±√(-1)^2-4x5x(-6)/2X5
x=1±√121/10
x=1±11/10
x1=1+11/10=6/5
x2=1-11/10=-1
4x^2-4x+1=0
x=-(-4)±√(-4)^2-4x4x1/2X4
x=4±√0/8
x=4±0/8
x1=x2=4±0/8=1/2
运用十字相乘法或公式法分解因式可以解答,得到X1和X2的值。