计算:1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+……+1/2^n

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/18 13:41:15
计算:1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+……+1/2^n
x){nuӭ M ̀1H $dh425~԰ @<"}JPl b';V=Ɏ @@˦\Syں)g<_ d

计算:1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+……+1/2^n
计算:1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+……+1/2^n

计算:1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+……+1/2^n
因为这个是一个以1/2为首项,1/2为公比的等比数列
所以上式等于1/2【1-(1/2)^n】/(1-1/2)=1-1/2^n

等于1
S=a1/(1-q)=1/2 /(1-1/2)=1

1-1/2^n