解析几何,直线位置.等腰三角形ABC,AB=AC.AB所在直线的方程是7x-y-9=0.AC边所在的直线方程是x+y-7=0.底边BC所在直线经过点P(3,-8),求:直线BC的方程,底角的大小、写大体思路我明白就行,不见得
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![解析几何,直线位置.等腰三角形ABC,AB=AC.AB所在直线的方程是7x-y-9=0.AC边所在的直线方程是x+y-7=0.底边BC所在直线经过点P(3,-8),求:直线BC的方程,底角的大小、写大体思路我明白就行,不见得](/uploads/image/z/13635083-11-3.jpg?t=%E8%A7%A3%E6%9E%90%E5%87%A0%E4%BD%95%2C%E7%9B%B4%E7%BA%BF%E4%BD%8D%E7%BD%AE.%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2ABC%2CAB%3DAC.AB%E6%89%80%E5%9C%A8%E7%9B%B4%E7%BA%BF%E7%9A%84%E6%96%B9%E7%A8%8B%E6%98%AF7x-y-9%3D0.AC%E8%BE%B9%E6%89%80%E5%9C%A8%E7%9A%84%E7%9B%B4%E7%BA%BF%E6%96%B9%E7%A8%8B%E6%98%AFx%EF%BC%8By%EF%BC%8D7%EF%BC%9D0.%E5%BA%95%E8%BE%B9BC%E6%89%80%E5%9C%A8%E7%9B%B4%E7%BA%BF%E7%BB%8F%E8%BF%87%E7%82%B9P%283%2C-8%29%2C%E6%B1%82%EF%BC%9A%E7%9B%B4%E7%BA%BFBC%E7%9A%84%E6%96%B9%E7%A8%8B%2C%E5%BA%95%E8%A7%92%E7%9A%84%E5%A4%A7%E5%B0%8F%E3%80%81%E5%86%99%E5%A4%A7%E4%BD%93%E6%80%9D%E8%B7%AF%E6%88%91%E6%98%8E%E7%99%BD%E5%B0%B1%E8%A1%8C%2C%E4%B8%8D%E8%A7%81%E5%BE%97)
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