matlab 时间序列模型求解yt=[101.5 102.7 102.4 102.8 103.1 102.9 103.3 103.5 103.6 104.4 105.1 104.6 104.9 104.9 105.4 105.3 105.5 106.4 106.5]n=length(yt); alpha=0.2; st1(1)=yt(1); st2(1)=yt(1); for i=2:n st1(i)=alpha*yt(i)+(1-alpha)*st1(i-1)s
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![matlab 时间序列模型求解yt=[101.5 102.7 102.4 102.8 103.1 102.9 103.3 103.5 103.6 104.4 105.1 104.6 104.9 104.9 105.4 105.3 105.5 106.4 106.5]n=length(yt); alpha=0.2; st1(1)=yt(1); st2(1)=yt(1); for i=2:n st1(i)=alpha*yt(i)+(1-alpha)*st1(i-1)s](/uploads/image/z/13638837-21-7.jpg?t=matlab+%E6%97%B6%E9%97%B4%E5%BA%8F%E5%88%97%E6%A8%A1%E5%9E%8B%E6%B1%82%E8%A7%A3yt%3D%5B101.5+102.7+102.4+102.8+103.1+102.9+103.3+103.5+103.6+104.4+105.1+104.6+104.9+104.9+105.4+105.3+105.5+106.4+106.5%5Dn%3Dlength%28yt%29%3B+alpha%3D0.2%3B+st1%281%29%3Dyt%281%29%3B+st2%281%29%3Dyt%281%29%3B+for+i%3D2%3An+st1%28i%29%3Dalpha%2Ayt%28i%29%2B%281-alpha%29%2Ast1%28i-1%29s)
matlab 时间序列模型求解yt=[101.5 102.7 102.4 102.8 103.1 102.9 103.3 103.5 103.6 104.4 105.1 104.6 104.9 104.9 105.4 105.3 105.5 106.4 106.5]n=length(yt); alpha=0.2; st1(1)=yt(1); st2(1)=yt(1); for i=2:n st1(i)=alpha*yt(i)+(1-alpha)*st1(i-1)s
matlab 时间序列模型求解
yt=[101.5 102.7 102.4 102.8 103.1 102.9 103.3 103.5 103.6 104.4 105.1 104.6 104.9 104.9 105.4 105.3 105.5 106.4 106.5]
n=length(yt);
alpha=0.2; st1(1)=yt(1); st2(1)=yt(1);
for i=2:n
st1(i)=alpha*yt(i)+(1-alpha)*st1(i-1)
st2(i)=alpha*st1(i)+(1-alpha)*st2(i-1)
end
%xlswrite('cpi2.xls',[st1',st2'])
a=2*st1-st2
b=alpha/(1-alpha)*(st1-st2)
yhat=a+b
%xlswrite('cpi2.xls',yhat','Sheet1','C2')
str=char(['C',int2str(n+2)]);
c=a(n)+b(n)
z=yhat-yt
plot(1:n,yt,'*',1:n,yhat(1:n),'O')
legend('实际值','预测值',2)
将这段代码中的yt=[101.5 102.7 102.4 102.8 103.1 102.9 103.3
103.5 103.6 104.4 105.1 104.6 104.9 104.9 105.4
105.3 105.5 106.4 106.5]改为yt=[102.7 104.0 103.2 104.9 105.0 104.7 106.1 106.5 105.9 104.1 103.7 102.7 104.1】即把19个数据改为13个数据,需要改其他地方的什么代码才能成功运行?
matlab 时间序列模型求解yt=[101.5 102.7 102.4 102.8 103.1 102.9 103.3 103.5 103.6 104.4 105.1 104.6 104.9 104.9 105.4 105.3 105.5 106.4 106.5]n=length(yt); alpha=0.2; st1(1)=yt(1); st2(1)=yt(1); for i=2:n st1(i)=alpha*yt(i)+(1-alpha)*st1(i-1)s
把yt数据换了,最前面再加上一句clear st1 st2就可以了(或者更简单一点,直接clear也行).