求证FG=1/2(AB+AC-BC)如图三角形ABC,BD,CE平分∠ABC,∠ACB,求证FG=1/2(AB+AC-BC)辅助线:延长AG AF交BC于MN
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![求证FG=1/2(AB+AC-BC)如图三角形ABC,BD,CE平分∠ABC,∠ACB,求证FG=1/2(AB+AC-BC)辅助线:延长AG AF交BC于MN](/uploads/image/z/13692834-18-4.jpg?t=%E6%B1%82%E8%AF%81FG%3D1%2F2%28AB%2BAC-BC%29%E5%A6%82%E5%9B%BE%E4%B8%89%E8%A7%92%E5%BD%A2ABC%2CBD%2CCE%E5%B9%B3%E5%88%86%E2%88%A0ABC%2C%E2%88%A0ACB%2C%E6%B1%82%E8%AF%81FG%3D1%2F2%28AB%2BAC-BC%29%E8%BE%85%E5%8A%A9%E7%BA%BF%EF%BC%9A%E5%BB%B6%E9%95%BFAG+AF%E4%BA%A4BC%E4%BA%8EMN)
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