高手来高一数学正余弦定理easy题[1]判断三角形形状.AB为锐角,cosA大于sinB[2](a+b+c)(a+b-c)=3ab且sinC=2sinAcosB.判断三角形形状[3]若S=(a^2+b^2-c^2)/4.求角C[4]若b=4,c=7,B=30度.求三角形面积.[5]2b=a+c.B=30度.S=3/2.
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/08 04:52:55
![高手来高一数学正余弦定理easy题[1]判断三角形形状.AB为锐角,cosA大于sinB[2](a+b+c)(a+b-c)=3ab且sinC=2sinAcosB.判断三角形形状[3]若S=(a^2+b^2-c^2)/4.求角C[4]若b=4,c=7,B=30度.求三角形面积.[5]2b=a+c.B=30度.S=3/2.](/uploads/image/z/13756925-29-5.jpg?t=%E9%AB%98%E6%89%8B%E6%9D%A5%E9%AB%98%E4%B8%80%E6%95%B0%E5%AD%A6%E6%AD%A3%E4%BD%99%E5%BC%A6%E5%AE%9A%E7%90%86easy%E9%A2%98%5B1%5D%E5%88%A4%E6%96%AD%E4%B8%89%E8%A7%92%E5%BD%A2%E5%BD%A2%E7%8A%B6.AB%E4%B8%BA%E9%94%90%E8%A7%92%2CcosA%E5%A4%A7%E4%BA%8EsinB%5B2%5D%28a%2Bb%2Bc%29%28a%2Bb-c%29%3D3ab%E4%B8%94sinC%3D2sinAcosB.%E5%88%A4%E6%96%AD%E4%B8%89%E8%A7%92%E5%BD%A2%E5%BD%A2%E7%8A%B6%5B3%5D%E8%8B%A5S%3D%28a%5E2%2Bb%5E2-c%5E2%29%2F4.%E6%B1%82%E8%A7%92C%5B4%5D%E8%8B%A5b%3D4%2Cc%3D7%2CB%3D30%E5%BA%A6.%E6%B1%82%E4%B8%89%E8%A7%92%E5%BD%A2%E9%9D%A2%E7%A7%AF.%5B5%5D2b%3Da%2Bc.B%3D30%E5%BA%A6.S%3D3%2F2.)
xSn@tlR a>muMJ7ݡ*M0
mQ"pȁl*Dž"S*ج4]V3{33rvvaVaUQgC4蕧^GKi툽s|
7t҃/szVGェ