求解[(向量a·向量b)·向量c]的绝对值,具体条件见补充说明!已知a的模=3,b的模=2,c的模=5,向量a与b的夹角为π/6,向量b与c的夹角为π/3,计算:(1).[(向量a·向量b)·向量c]的绝对值(2).[向量a
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![求解[(向量a·向量b)·向量c]的绝对值,具体条件见补充说明!已知a的模=3,b的模=2,c的模=5,向量a与b的夹角为π/6,向量b与c的夹角为π/3,计算:(1).[(向量a·向量b)·向量c]的绝对值(2).[向量a](/uploads/image/z/13825549-37-9.jpg?t=%E6%B1%82%E8%A7%A3%5B%EF%BC%88%E5%90%91%E9%87%8Fa%C2%B7%E5%90%91%E9%87%8Fb%EF%BC%89%C2%B7%E5%90%91%E9%87%8Fc%5D%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%2C%E5%85%B7%E4%BD%93%E6%9D%A1%E4%BB%B6%E8%A7%81%E8%A1%A5%E5%85%85%E8%AF%B4%E6%98%8E%21%E5%B7%B2%E7%9F%A5a%E7%9A%84%E6%A8%A1%3D3%2Cb%E7%9A%84%E6%A8%A1%3D2%2Cc%E7%9A%84%E6%A8%A1%3D5%2C%E5%90%91%E9%87%8Fa%E4%B8%8Eb%E7%9A%84%E5%A4%B9%E8%A7%92%E4%B8%BA%CF%80%2F6%2C%E5%90%91%E9%87%8Fb%E4%B8%8Ec%E7%9A%84%E5%A4%B9%E8%A7%92%E4%B8%BA%CF%80%2F3%2C%E8%AE%A1%E7%AE%97%EF%BC%9A%EF%BC%881%EF%BC%89.%5B%EF%BC%88%E5%90%91%E9%87%8Fa%C2%B7%E5%90%91%E9%87%8Fb%EF%BC%89%C2%B7%E5%90%91%E9%87%8Fc%5D%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%EF%BC%882%EF%BC%89.%5B%E5%90%91%E9%87%8Fa)
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