已知(2x-1)^5=a0+a1x+a2x^2+a3x^3+a4x^4+a5x^5 求下列各式的值(1)a0+a1+a2+a3+a4+a5(2)a0-a1+a2-a3+a4-a5(3)a0+a2+a4再帮个忙:计算:(a1=a2+……an-10)(a2+a3+……+an)-(a2+a3+……+an-1)(a1+a2+……+an)a1这些与上一题
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![已知(2x-1)^5=a0+a1x+a2x^2+a3x^3+a4x^4+a5x^5 求下列各式的值(1)a0+a1+a2+a3+a4+a5(2)a0-a1+a2-a3+a4-a5(3)a0+a2+a4再帮个忙:计算:(a1=a2+……an-10)(a2+a3+……+an)-(a2+a3+……+an-1)(a1+a2+……+an)a1这些与上一题](/uploads/image/z/13919174-62-4.jpg?t=%E5%B7%B2%E7%9F%A5%282x-1%29%5E5%3Da0%2Ba1x%2Ba2x%5E2%2Ba3x%5E3%2Ba4x%5E4%2Ba5x%5E5+%E6%B1%82%E4%B8%8B%E5%88%97%E5%90%84%E5%BC%8F%E7%9A%84%E5%80%BC%EF%BC%881%EF%BC%89a0%2Ba1%2Ba2%2Ba3%2Ba4%2Ba5%EF%BC%882%EF%BC%89a0-a1%2Ba2-a3%2Ba4-a5%EF%BC%883%EF%BC%89a0%2Ba2%2Ba4%E5%86%8D%E5%B8%AE%E4%B8%AA%E5%BF%99%EF%BC%9A%E8%AE%A1%E7%AE%97%EF%BC%9A%EF%BC%88a1%3Da2%2B%E2%80%A6%E2%80%A6an-10%29%28a2%2Ba3%2B%E2%80%A6%E2%80%A6%2Ban%29-%28a2%2Ba3%2B%E2%80%A6%E2%80%A6%2Ban-1%29%28a1%2Ba2%2B%E2%80%A6%E2%80%A6%2Ban%29a1%E8%BF%99%E4%BA%9B%E4%B8%8E%E4%B8%8A%E4%B8%80%E9%A2%98)
已知(2x-1)^5=a0+a1x+a2x^2+a3x^3+a4x^4+a5x^5 求下列各式的值(1)a0+a1+a2+a3+a4+a5(2)a0-a1+a2-a3+a4-a5(3)a0+a2+a4再帮个忙:计算:(a1=a2+……an-10)(a2+a3+……+an)-(a2+a3+……+an-1)(a1+a2+……+an)a1这些与上一题
已知(2x-1)^5=a0+a1x+a2x^2+a3x^3+a4x^4+a5x^5 求下列各式的值
(1)a0+a1+a2+a3+a4+a5
(2)a0-a1+a2-a3+a4-a5
(3)a0+a2+a4
再帮个忙:计算:(a1=a2+……an-10)(a2+a3+……+an)-(a2+a3+……+an-1)(a1+a2+……+an)
a1这些与上一题一样不代表乘
已知(2x-1)^5=a0+a1x+a2x^2+a3x^3+a4x^4+a5x^5 求下列各式的值(1)a0+a1+a2+a3+a4+a5(2)a0-a1+a2-a3+a4-a5(3)a0+a2+a4再帮个忙:计算:(a1=a2+……an-10)(a2+a3+……+an)-(a2+a3+……+an-1)(a1+a2+……+an)a1这些与上一题
(1)令x=1,得a0+a1+a2+a3+a4+a5=(2×1-1)5=1;
(2)令x=-l,得a0-a1+a2-a3+a4-a5=[2×(-1)-1]5=-243;
(3)将上面两式相加,得2a0+2a2+2a4=-242,
解得a0+a2+a4=-121.
x=1 a0+a1+a2+a3+a4+a5=(2-1)^5=1
x=-1 a0-a1+a2-a3+a4-a5=(2x-1)^5=(-3)^5
a0+a1+a2+a3+a4+a5+a0-a1+a2-a3+a4-a5=(a0+a2+a4)x2=(2-1)^5+(-3)^5
分别对X进行赋值,另X等于正负1可的一二问分别为1,-243 第三问一二相加再除2得-121