一道简单的线性代数设A=(0 1)(2 -2)f(x)=|x-1 x 0 || 0 x-1 2||1 2 2|则f(A)=?答案是(10 -10)(-20 30)f(x)是个行列式怎么算的啊,如果把行列式的值算出来,最后减去是个常数,可是矩阵不是不能减常
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![一道简单的线性代数设A=(0 1)(2 -2)f(x)=|x-1 x 0 || 0 x-1 2||1 2 2|则f(A)=?答案是(10 -10)(-20 30)f(x)是个行列式怎么算的啊,如果把行列式的值算出来,最后减去是个常数,可是矩阵不是不能减常](/uploads/image/z/13942407-39-7.jpg?t=%E4%B8%80%E9%81%93%E7%AE%80%E5%8D%95%E7%9A%84%E7%BA%BF%E6%80%A7%E4%BB%A3%E6%95%B0%E8%AE%BEA%3D%EF%BC%880+1%EF%BC%89%EF%BC%882+-2%EF%BC%89f%28x%29%3D%7Cx-1+x+0+%7C%7C+0+x-1+2%7C%7C1+2+2%7C%E5%88%99f%28A%29%3D%3F%E7%AD%94%E6%A1%88%E6%98%AF%EF%BC%8810+-10%EF%BC%89%EF%BC%88-20+30%EF%BC%89f%28x%29%E6%98%AF%E4%B8%AA%E8%A1%8C%E5%88%97%E5%BC%8F%E6%80%8E%E4%B9%88%E7%AE%97%E7%9A%84%E5%95%8A%2C%E5%A6%82%E6%9E%9C%E6%8A%8A%E8%A1%8C%E5%88%97%E5%BC%8F%E7%9A%84%E5%80%BC%E7%AE%97%E5%87%BA%E6%9D%A5%2C%E6%9C%80%E5%90%8E%E5%87%8F%E5%8E%BB%E6%98%AF%E4%B8%AA%E5%B8%B8%E6%95%B0%2C%E5%8F%AF%E6%98%AF%E7%9F%A9%E9%98%B5%E4%B8%8D%E6%98%AF%E4%B8%8D%E8%83%BD%E5%87%8F%E5%B8%B8)
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