已知x,y,z∈R,且x+y+z=8,x^2+y^2+z^2=24,求证:4/3≤x≤3,4/3≤y≤3,4/3≤z≤3
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![已知x,y,z∈R,且x+y+z=8,x^2+y^2+z^2=24,求证:4/3≤x≤3,4/3≤y≤3,4/3≤z≤3](/uploads/image/z/13949043-51-3.jpg?t=%E5%B7%B2%E7%9F%A5x%2Cy%2Cz%E2%88%88R%2C%E4%B8%94x%2By%2Bz%3D8%2Cx%5E2%2By%5E2%2Bz%5E2%3D24%2C%E6%B1%82%E8%AF%81%3A4%2F3%E2%89%A4x%E2%89%A43%2C4%2F3%E2%89%A4y%E2%89%A43%2C4%2F3%E2%89%A4z%E2%89%A43)
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