二次函数解直角坐标系如图,在直角坐标系中放入一个边长OC为9的矩形纸片ABCO,将纸片翻折后,点B恰好落在x轴上,记为B',折痕为CE,已知tan角OB'C=3\4(1)求B'点的坐标(2)求折痕CE所在直线的解析式
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![二次函数解直角坐标系如图,在直角坐标系中放入一个边长OC为9的矩形纸片ABCO,将纸片翻折后,点B恰好落在x轴上,记为B',折痕为CE,已知tan角OB'C=3\4(1)求B'点的坐标(2)求折痕CE所在直线的解析式](/uploads/image/z/14139529-25-9.jpg?t=%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0%E8%A7%A3%E7%9B%B4%E8%A7%92%E5%9D%90%E6%A0%87%E7%B3%BB%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E7%9B%B4%E8%A7%92%E5%9D%90%E6%A0%87%E7%B3%BB%E4%B8%AD%E6%94%BE%E5%85%A5%E4%B8%80%E4%B8%AA%E8%BE%B9%E9%95%BFOC%E4%B8%BA9%E7%9A%84%E7%9F%A9%E5%BD%A2%E7%BA%B8%E7%89%87ABCO%2C%E5%B0%86%E7%BA%B8%E7%89%87%E7%BF%BB%E6%8A%98%E5%90%8E%2C%E7%82%B9B%E6%81%B0%E5%A5%BD%E8%90%BD%E5%9C%A8x%E8%BD%B4%E4%B8%8A%2C%E8%AE%B0%E4%B8%BAB%27%2C%E6%8A%98%E7%97%95%E4%B8%BACE%2C%E5%B7%B2%E7%9F%A5tan%E8%A7%92OB%27C%3D3%5C4%EF%BC%881%EF%BC%89%E6%B1%82B%27%E7%82%B9%E7%9A%84%E5%9D%90%E6%A0%87%EF%BC%882%29%E6%B1%82%E6%8A%98%E7%97%95CE%E6%89%80%E5%9C%A8%E7%9B%B4%E7%BA%BF%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F)
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