甲烷燃料电池方程式负极:CH4+10OH--8e-=CO3²﹣+7H2O 正极:2O2+4H2O- +8e-=8OH- 总方程式:CH4+2O2=CO2+2H2O CO2+2OH-=CO3²﹣+H2O和为 CH4+2O2+2OH﹣=CO3²﹣+3H2O为何最后与甲烷燃烧方程式不同
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/05 18:41:07
xXn~ hkɇH\rMcMܴPkR2W-dbwU5Oz|U3N\&_K_܊pdD7N[b}7zi33_wo?ܷ=/|Ϻ^9V>3c!yp:zǕ-<>kG5mƭ Qjnmzj%]DjZ _O/~{yH_aCjD$b~HX!"9(,xj=cX,_R(GVib"}#0X(4R{`!X>QBbRa4YsPfLsJ5CV"R f]ҩxrB (N̾.GPD5/QHA$
J
C":>1
#XMsd̷17%sO睅mW/YSS/y&}zb,%f])(q_ $C~6%>L)ߩwm7yIprT_ϲVK wNd-cI,r.%|W0X|UFGd4nC?mz@YR/-n;TÁC,B@8rTCnࡗ8*C3Le8GQ~8aK(x3tE@ {)R)4Ch|;l|oinEڗKF?֩/HK H}lFxf]'z &7 )<S5)J,:HXr(GGO|Nw(pVńe\$GqUNrEDBZ*8(*u{Ea,g?ۈ"K
ih2)zAG>8Bu 5a'nv
LDV@ՓeD9g1ꚫiq@)dGhlP;{_^m_^ԺuC
Sq*JW-P}h 4Yr
K5_FLhT4Ն謲J\IVBZ"M!zq,y,ÅIn{
#_/bFqf3%1;9Mʔ+[D
_RS