已知函数F(X)=2sin(2x/3+π/6)-1在三角形ABC中,若F(B)=1,且2sin²C-cosC=sin(B-C),求角B与cosC的值
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![已知函数F(X)=2sin(2x/3+π/6)-1在三角形ABC中,若F(B)=1,且2sin²C-cosC=sin(B-C),求角B与cosC的值](/uploads/image/z/14266717-61-7.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0F%28X%29%3D2sin%282x%2F3%2B%CF%80%2F6%29-1%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%8B%A5F%28B%29%3D1%2C%E4%B8%942sin%26%23178%3BC-cosC%3Dsin%28B-C%29%2C%E6%B1%82%E8%A7%92B%E4%B8%8EcosC%E7%9A%84%E5%80%BC)
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