用Matlab解一个方程组,结果如下,请问怎么回事?是方程组无解吗?S1= -cos(deg2rad(10.11))*41;S2= 31.5*cos(deg2rad(10.11))+85*sin(deg2rad(10.11));S3=sin(deg2rad(10.11));S4= -cos(deg2rad(10.11));B1=-12544;B2=-12544*50;B3=12544*22.5;B4=
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![用Matlab解一个方程组,结果如下,请问怎么回事?是方程组无解吗?S1= -cos(deg2rad(10.11))*41;S2= 31.5*cos(deg2rad(10.11))+85*sin(deg2rad(10.11));S3=sin(deg2rad(10.11));S4= -cos(deg2rad(10.11));B1=-12544;B2=-12544*50;B3=12544*22.5;B4=](/uploads/image/z/14278104-0-4.jpg?t=%E7%94%A8Matlab%E8%A7%A3%E4%B8%80%E4%B8%AA%E6%96%B9%E7%A8%8B%E7%BB%84%2C%E7%BB%93%E6%9E%9C%E5%A6%82%E4%B8%8B%2C%E8%AF%B7%E9%97%AE%E6%80%8E%E4%B9%88%E5%9B%9E%E4%BA%8B%3F%E6%98%AF%E6%96%B9%E7%A8%8B%E7%BB%84%E6%97%A0%E8%A7%A3%E5%90%97%3FS1%3D+-cos%28deg2rad%2810.11%29%29%2A41%3BS2%3D+31.5%2Acos%28deg2rad%2810.11%29%29%2B85%2Asin%28deg2rad%2810.11%29%29%3BS3%3Dsin%28deg2rad%2810.11%29%29%3BS4%3D+-cos%28deg2rad%2810.11%29%29%3BB1%3D-12544%3BB2%3D-12544%2A50%3BB3%3D12544%2A22.5%3BB4%3D)
用Matlab解一个方程组,结果如下,请问怎么回事?是方程组无解吗?S1= -cos(deg2rad(10.11))*41;S2= 31.5*cos(deg2rad(10.11))+85*sin(deg2rad(10.11));S3=sin(deg2rad(10.11));S4= -cos(deg2rad(10.11));B1=-12544;B2=-12544*50;B3=12544*22.5;B4=
用Matlab解一个方程组,结果如下,请问怎么回事?是方程组无解吗?
S1= -cos(deg2rad(10.11))*41;
S2= 31.5*cos(deg2rad(10.11))+85*sin(deg2rad(10.11));
S3=sin(deg2rad(10.11));
S4= -cos(deg2rad(10.11));
B1=-12544;
B2=-12544*50;
B3=12544*22.5;
B4=0;
A=[ 1 ,S4 ,-1,0;
0 ,S1 ,-72.5 ,85;
-72.5,S2 ,0 ,0;
0 ,S3 ,0 ,-1];
B=[B1;B2;B3;B4];
x=inv(A)*B;
Warning:Matrix is close to singular or badly scaled.Results may be
inaccurate.RCOND = 1.031673e-19.
用Matlab解一个方程组,结果如下,请问怎么回事?是方程组无解吗?S1= -cos(deg2rad(10.11))*41;S2= 31.5*cos(deg2rad(10.11))+85*sin(deg2rad(10.11));S3=sin(deg2rad(10.11));S4= -cos(deg2rad(10.11));B1=-12544;B2=-12544*50;B3=12544*22.5;B4=
他的意思是说A不可逆,得到的答案很可能是错误的
你可以试试看rank(A),你会发现A的秩=3,不是4,所以A根本不可逆