10^(2-lg2)=

lg2+lg2^2+lg2^3+……+lg2^10= 10^(2-lg2)= 求值 ：lg5²+lg2*lg50+(lg2)²答案写；2lg5+lg2*lg(5*10)+(lg2)²①=2lg5+lg2*lg5+lg2+(lg2)² ②=2lg5+lg2*(lg5+lg2)+lg2③ .第 ②步怎么得到的怎么就变成了lg2*lg5+lg2? (lg2)^2+lg2*lg5+(lg5)^2= (lg2^2+1)(lg2)^2+1=? lg25+lg2·lg50+(lg2)^2=? lg50+lg2*lg5+(lg2)^2= lg25+lg2*lg50+(lg2)^2+1=? lg^2 5+lg2*lg5+lg2=? lg5*(1+lg2)+(lg2)^2= lg5+2lg2+（lg2）=? lg5+2lg2-lg2=什么 lg2*lg100 =lg25+2lg2 lg2*lg2+lg5-lg2=? 2lg2+lg5/lg√10=? 2lg5*lg2= 1/2(lg2)^2+1/2lg2*lg5+√1/4(lg2)^2-lg2+1=? =(lg5)^2+lg2×lg5+lg2 =lg5×(lg5+lg2)+lg2麻烦问一下,这是咋做的