假定输入为”Go west,young man!”,以下程序会产生什么样的输出?#include void main(){char ch;scanf("%c",&ch);while(ch!='g'){printf("%c",ch);scanf("%c",&ch);}}请问为什么在while循环中只执行输出,没执行输入?
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假定输入为”Go west,young man!”,以下程序会产生什么样的输出?#include void main(){char ch;scanf("%c",&ch);while(ch!='g'){printf("%c",ch);scanf("%c",&ch);}}请问为什么在while循环中只执行输出,没执行输入?
假定输入为”Go west,young man!”,以下程序会产生什么样的输出?
#include
void main()
{
char ch;
scanf("%c",&ch);
while(ch!='g')
{
printf("%c",ch);
scanf("%c",&ch);
}
}
请问为什么在while循环中只执行输出,没执行输入?
假定输入为”Go west,young man!”,以下程序会产生什么样的输出?#include void main(){char ch;scanf("%c",&ch);while(ch!='g'){printf("%c",ch);scanf("%c",&ch);}}请问为什么在while循环中只执行输出,没执行输入?
哈哈,看来你是初学者啊,没事儿,好好学啊.你输入的是一个字符串.
而%c是字符型,%s是字符串型.所以ch只接收了你一个字符,即‘G’.大些G与小写G的码值不一样(ASCII码,大小写数值相隔32,你可以看看那ASCII表).进入循环后,如果你输入'g',此时ch变成了g,循环就终止了.至于你问的没执行输入我表示你可能弄错了,如果你一个个输,不含g,还是可以输出你所输入的.
C语言问题(假定输入为Go west,young man!)#includeint mian(void){char ch;scanf(%c,&ch);for(ch='$';ch!='g';scanf(%c,&ch))putchar(ch);return 0; }
假定输入为”Go west,young man!”,以下程序会产生什么样的输出?#include void main(){char ch;scanf(%c,&ch);while(ch!='g'){printf(%c,ch);scanf(%c,&ch);}}请问为什么在while循环中只执行输出,没执行输入?
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